TV tower

Calculate the height of the television tower if an observer standing 430 m from the base of the tower sees the peak at an altitude angle of 23°?

Correct result:

y =  182.524 m

Solution:

x=430 m A=23   tanA=yx  y=x tanA=x tan23 =430 tan23 =430 0.424475=182.524 mx=430 \ \text{m} \ \\ A=23 \ ^\circ \ \\ \ \\ \tan A=\dfrac{ y }{ x } \ \\ \ \\ y=x \cdot \ \tan A ^\circ =x \cdot \ \tan 23^\circ \ =430 \cdot \ \tan 23^\circ \ =430 \cdot \ 0.424475=182.524 \ \text{m}



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