AP - simple

Determine the first nine elements of sequence if a10 = -1 and d = 4

Result

a9 =  -5
a8 =  -9
a7 =  -13
a6 =  -17
a5 =  -21
a4 =  -25
a3 =  -29
a2 =  -33
a1 =  -37

Solution:

a9=−1−4=−5a_9=-1-4=-5
a8=−5−4=−9a_8=-5-4=-9
a7=−9−4=−13a_7=-9-4=-13
a6=−13−4=−17a_6=-13-4=-17
a5=−17−4=−21a_5=-17-4=-21
a4=−21−4=−25a_4=-21-4=-25
a3=−25−4=−29a_3=-25-4=-29
a2=−29−4=−33a_2=-29-4=-33
a1=−33−4=−37a_1=-33-4=-37

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