# AP - simple

Determine the first nine elements of sequence if a10 = -1 and d = 4

Correct result:

a9 =  -5
a8 =  -9
a7 =  -13
a6 =  -17
a5 =  -21
a4 =  -25
a3 =  -29
a2 =  -33
a1 =  -37

#### Solution:

${a}_{9}=-1-4=-5$
${a}_{8}=-5-4=-9$
${a}_{7}=-9-4=-13$
${a}_{6}=-13-4=-17$
${a}_{5}=-17-4=-21$
${a}_{4}=-21-4=-25$
${a}_{3}=-25-4=-29$
${a}_{2}=-29-4=-33$
${a}_{1}=-33-4=-37$

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