# AP - simple

Determine the first nine elements of sequence if a10 = -1 and d = 4

Result

a9 =  -5
a8 =  -9
a7 =  -13
a6 =  -17
a5 =  -21
a4 =  -25
a3 =  -29
a2 =  -33
a1 =  -37

#### Solution:

$a_9=-1-4 = -5$
$a_8=-5-4 = -9$
$a_7=-9-4 = -13$
$a_6=-13-4 = -17$
$a_5=-17-4 = -21$
$a_4=-21-4 = -25$
$a_3=-25-4 = -29$
$a_2=-29-4 = -33$
$a_1=-33-4 = -37$

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