Six terms

Find the first six terms of the sequence
a1 = -3, an = 2 * an-1

Correct result:

a1 =  -3
a2 =  -6
a3 =  -12
a4 =  -24
a5 =  -48
a6 =  -96

Solution:

a1=−3a_{1}=-3
a2=2⋅ a1=2⋅ (−3)=−6a_{2}=2 \cdot \ a_{1}=2 \cdot \ (-3)=-6
a3=2⋅ a2=2⋅ (−6)=−12a_{3}=2 \cdot \ a_{2}=2 \cdot \ (-6)=-12
a4=2⋅ a3=2⋅ (−12)=−24a_{4}=2 \cdot \ a_{3}=2 \cdot \ (-12)=-24
a5=2⋅ a4=2⋅ (−24)=−48a_{5}=2 \cdot \ a_{4}=2 \cdot \ (-24)=-48
a6=2⋅ a5=2⋅ (−48)=−96a_{6}=2 \cdot \ a_{5}=2 \cdot \ (-48)=-96

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