Six terms

Find the first six terms of the sequence
a1 = -3, an = 2 * an-1

Correct result:

a1 =  -3
a2 =  -6
a3 =  -12
a4 =  -24
a5 =  -48
a6 =  -96

Solution:

$a_{1}=-3$
$a_{2}=2 \cdot \ a_{1}=2 \cdot \ (-3)=-6$
$a_{3}=2 \cdot \ a_{2}=2 \cdot \ (-6)=-12$
$a_{4}=2 \cdot \ a_{3}=2 \cdot \ (-12)=-24$
$a_{5}=2 \cdot \ a_{4}=2 \cdot \ (-24)=-48$
$a_{6}=2 \cdot \ a_{5}=2 \cdot \ (-48)=-96$

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