Six terms

Find the first six terms of the sequence
a1 = -3, an = 2 * an-1

Correct result:

a₁ =  -3
a₂ =  -6
a₃ =  -12
a₄ =  -24
a₅ =  -48
a₆ =  -96

Solution:

$a_1=-3$

$a_2=2\cdot a_1=2\cdot (-3)=-6$

$a_3=2\cdot a_2=2\cdot (-6)=-12$

$a_4=2\cdot a_3=2\cdot (-12)=-24$

$a_5=2\cdot a_4=2\cdot (-24)=-48$

$a_6=2\cdot a_5=2\cdot (-48)=-96$

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