Six terms

Find the first six terms of the sequence
a1 = -3, an = 2 * an-1

Result

a1 =  -3
a2 =  -6
a3 =  -12
a4 =  -24
a5 =  -48
a6 =  -96

Solution:

a1=3a_{1}=-3
a2=2 a1=2 (3)=6a_{2}=2 \cdot \ a_{1}=2 \cdot \ (-3)=-6
a3=2 a2=2 (6)=12a_{3}=2 \cdot \ a_{2}=2 \cdot \ (-6)=-12
a4=2 a3=2 (12)=24a_{4}=2 \cdot \ a_{3}=2 \cdot \ (-12)=-24
a5=2 a4=2 (24)=48a_{5}=2 \cdot \ a_{4}=2 \cdot \ (-24)=-48
a6=2 a5=2 (48)=96a_{6}=2 \cdot \ a_{5}=2 \cdot \ (-48)=-96



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