6 terms

Find the first six terms of the sequence.

a1 = 7, an = an-1 + 6

Correct result:

a1 =  7
a2 =  13
a3 =  19
a4 =  25
a5 =  31
a6 =  37

Solution:

a1=7a_{1}=7
a2=7+6=13a_{2}=7+6=13
a3=13+6=19a_{3}=13+6=19
a4=19+6=25a_{4}=19+6=25
a5=25+6=31a_{5}=25+6=31
a6=31+6=37a_{6}=31+6=37



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