# 6 terms

Find the first six terms of the sequence.

a1 = 7, an = an-1 + 6

Correct result:

a1 =  7
a2 =  13
a3 =  19
a4 =  25
a5 =  31
a6 =  37

#### Solution:

$a_{1}=7$
$a_{2}=7+6=13$
$a_{3}=13+6=19$
$a_{4}=19+6=25$
$a_{5}=25+6=31$
$a_{6}=31+6=37$

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