AP with variables

What is the second member in the arithmetic sequence with 7 terms, whose first and last terms are x+2y and 7x-4y

Correct answer:

a2 = 2x+y

Step-by-step explanation:

a1=x+2y a7 = 7x4y  a7 = a1 + 6d  d= 6a7a1 = 67x4y  x2y  d = 66x6y = xy  a2=a1 + d a2 = x+2y+(xy)  a2=2x+y

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