Receiving heat

How many degrees Celsius was an iron cylinder weighing 300 g heated in a water bath if it received heat of 7.2 kJ? (specific heat capacity of iron c = 0.46kJ/kg / ºC)

Correct result:

t =  52.1739 °C

Solution:

$$\begin{gathered} m=300\text{ g}\to \text{ kg}=300\mathrm{/}1000\text{ kg}=0.3\text{ kg } \\ Q=7.2\text{ kJ } \\ c=0.46{\text{kJ/kg/}}^{\circ } \\ Q=mct \\ t={\displaystyle \frac{Q}{m\cdot c}}={\displaystyle \frac{7.2}{0.3\cdot 0.46}}={\displaystyle \frac{1200}{23}}=52.1739^{\circ }\text{C} \end{gathered}$$

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