Receiving heat

How many degrees Celsius was an iron cylinder weighing 300 g heated in a water bath if it received heat of 7.2 kJ? (specific heat capacity of iron c = 0.46kJ/kg / ºC)

Correct result:

t =  52.174 °C

Solution:

m=300 gkg=300/1000 kg=0.3 kg Q=7.2 kJ c=0.46 kJ/kg/  Q=mct  t=Qm c=7.20.3 0.46=120023=52.174Cm=300 \ g \rightarrow kg=300 / 1000 \ kg=0.3 \ kg \ \\ Q=7.2 \ \text{kJ} \ \\ c=0.46 \ \text{kJ/kg/}^\circ \ \\ \ \\ Q=m c t \ \\ \ \\ t=\dfrac{ Q }{ m \cdot \ c }=\dfrac{ 7.2 }{ 0.3 \cdot \ 0.46 }=\dfrac{ 1200 }{ 23 }=52.174 ^\circ \text{C}



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