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How much heat must we supply to completely convert potassium weighing 45 kg at a temperature of 22.4 °C into potassium at a temperature of 98 °C? The specific heat of fusion is 25.5 kJ/kg, the melting point is 63.32 °C. The specific heat capacity of potassium is 757.8 J/kg/K.

Correct answer:

Q =  3725.5 kJ

Step-by-step explanation:

m=45 kg t1=22.4 °C t2=98 °C l=25.5 1000=25500 J/kg c=757.8 J/kg/K  Q1=m c (t2t1)=45 757.8 (9822.4)=2578035.6 J Q2=m l=45 25500=1147500 J Q3=Q1+Q2=2578035.6+1147500=3725535.6 J  Q=Q3 kJ=Q3:1000  kJ=3725535.6:1000  kJ=3725.5 kJ=3725.5 kJ



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