Shoemaker

Both the shoemaker and his apprentice repaired his shoes. The apprentice worked for 6 days and repaired 10 pairs of shoes every day. The shoemaker did the same job in 4 days. How many pairs of shoes did the shoemaker repair per day?

Correct result:

x =  15

Solution:

$$\begin{gathered} u=6\cdot 10=60 \\ x=u\mathrm{/}4=60\mathrm{/}4=15 \end{gathered}$$

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