Bullet game

Three friends were playing bullets. They did not have the same number of marbles at the start of the game. They had them in a ratio of 2:7:5, while Mike and Jano had a total of 77 bullets. How many marbles did their friend Peter have at the beginning? Could everyone have the same number of bullets at the end of the game?

Result

p =  77
d=

Yes

No

Step-by-step explanation:

$$\begin{gathered} m:p:j=2:7:5 \\ s=77 \\ d=\frac{s}{2+5}=\frac{77}{2+5}=11 \\ m=2\cdot d=2\cdot 11=22 \\ j=5\cdot d=5\cdot 11=55 \\ p=7\cdot d=7\cdot 11=77 \end{gathered}$$

$$\begin{gathered} d_0=s/3=51.333\notin N \\ d=0 \end{gathered}$$

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