Remainder

What is the remainder of the division of natural numbers 293 and 7?

Correct result:

z =  6

Solution:

p=293/7=2937≐41.8571 p1=⌊p⌋=⌊41.8571⌋=41  z=293−p1⋅ 7=293−41⋅ 7=6

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