Remainder

What is the remainder of the division of natural numbers 293 and 7?

Correct answer:

z =  6

Step-by-step explanation:

$$\begin{gathered} p=293\mathrm{/}7={\displaystyle \frac{293}{7}}=41\frac{6}{7}\doteq 41.8571 \\ {p}_1=\lfloor p\rfloor =\lfloor 41.8571\rfloor =41 \\ z=293-p_1\cdot 7=293-41\cdot 7=6 \end{gathered}$$

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