By what percentage does the sound intensity increase if the sound intensity level increases by 1 dB?

Correct answer:

p =  25.8925 %

Step-by-step explanation:

L=1 dB L2=L/10=1/10=101=0.1 B  L2=log(q)  q=10L2=100.11.2589  p=100 (q1)=100 (1.25891)=25.8925%

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