Decibel

By what percentage does the sound intensity increase if the sound intensity level increases by 1 dB?

Correct result:

p =  25.8925 %

Solution:

L=1 dB L2=L/10=1/10=110=0.1 B  L2=log⁡(q)  q=10L2=100.1≐1.2589  p=100⋅ (q−1)=100⋅ (1.2589−1)=25.8925%

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