Percentage and rectangle

About what percentage increases perimeter and area of a rectangle if both the sides 12 cm and 10 cm long we increase by 20%?

Correct result:

p1 =  20 %
p2 =  44 %

Solution:

a=12 b=10 S=a⋅ b=12⋅ 10=120 o=2⋅ (a+b)=2⋅ (12+10)=44 a1=a⋅ 1.20=12⋅ 1.20=725=14.4 b1=b⋅ 1.20=10⋅ 1.20=12 S1=a1⋅ b1=14.4⋅ 12=8645=172.8 o1=2⋅ (a1+b1)=2⋅ (14.4+12)=2645=52.8 p1=p1=100⋅ (o1−o)/o=100⋅ (52.8−44)/44=20%
p2=p2=100⋅ (S1−S)/S=100⋅ (172.8−120)/120=44%

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