Percentage and rectangle

About what percentage increases perimeter and area of a rectangle if both the sides 12 cm and 10 cm long we increase by 20%?

Correct result:

p1 =  20 %
p2 =  44 %

Solution:

a=12 b=10 S=a b=12 10=120 o=2 (a+b)=2 (12+10)=44 a1=a 1.20=12 1.20=725=14.4 b1=b 1.20=10 1.20=12 S1=a1 b1=14.4 12=8645=172.8 o1=2 (a1+b1)=2 (14.4+12)=2645=52.8 p1=p1=100 (o1o)/o=100 (52.844)/44=20%
p2=p2=100 (S1S)/S=100 (172.8120)/120=44%



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