Remainder 34441

Find the remainder after division when we divide the sum of 1! +2! +3! +. ... . +300! number 13.

Correct answer:

x =  

Step-by-step explanation:

s1​=1!=1 z1​=mod(s1​,13)=mod1,13=1  s2​=s1​+2!=1+2!=3 z2​=mod(s2​,13)=mod3,13=3  s3​=s2​+3!=3+3!=9 z3​=mod(s3​,13)=mod9,13=9  s4​=s3​+4!=9+4!=33 z4​=mod(s4​,13)=mod33,13=7  s5​=s4​+5!=33+5!=153 z5​=mod(s5​,13)=mod153,13=10  s6​=s5​+6!=153+6!=873 x=z6​=mod(s6​,13)=mod873,13=2=

Try another example


Did you find an error or inaccuracy? Feel free to write us. Thank you!







You need to know the following knowledge to solve this word math problem:

algebraarithmeticbasic operations and conceptsGrade of the word problem

Related math problems and questions: