HP - harmonic progression 2

Compute the 16th term of the HP if the 6th and 11th term of the harmonic progression are 10 and 18 respectively.

Correct result:

h16 =  90

Solution:

h6=10 h11=18  a6=1/h6=1/10=110=0.1 a11=1/h11=1/18=1180.0556  d=(a11a6)/(116)=(0.05560.1)/(116)=22250.0089 a1=a65 d=0.15 (0.0089)=13900.1444  a16=a1+15 d=0.1444+15 (0.0089)=1900.0111  h16=1/a16=1/0.0111=90



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