The product 9

The product of the third and second terms of the arithmetic progression is 3000. If the common difference is 10, find the first term.

Final Answer:

a1 =  50
a2 =  -60

Step-by-step explanation:

d=10  b=a1+d  a b=3000 a (a+d)=3000  a (a+d)=3000  a (a+10)=3000 a2+10a3000=0  p=1;q=10;r=3000 D=q24pr=10241(3000)=12100 D>0  a1,2=2pq±D=210±12100 a1,2=210±110 a1,2=5±55 a1=50 a1=a2=60=50

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