Trapezium

The area of trapezium is 35 cm2. Find its altitude if the bases are 6cm and 8 cm.

Result

h =  5 cm

Solution:

a=6 c=8 S=35 S=(a+c)h/2 h=2⋅ S/(a+c)=2⋅ 35/(6+8)=5=5  cm a = 6 \ \\ c = 8 \ \\ S = 35 \ \\ S = (a+c)h/2 \ \\ h = 2 \cdot \ S/(a+c) = 2 \cdot \ 35/(6+8) = 5 = 5 \ \text{ cm }

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