Trapezoid perimeter area

In the trapezoid, it is given:
all four sides a = 51 cm; b = 30 cm; c = 18 cm; d = 27 cm; and height v = 24 cm;
Calculate: perimeter o=? and area S=?

Final Answer:

o =  126 cm
S =  828 cm²

Step-by-step explanation:

$$\begin{gathered} a=51\text{cm} \\ b=30\text{cm} \\ c=18\text{cm} \\ d=27\text{cm} \\ v=24\text{cm} \\ o=a+b+c+d=51+30+18+27=126\text{cm} \end{gathered}$$

$S=\frac{a+c}{2}\cdot v=\frac{51+18}{2}\cdot 24=828{\text{cm}}^2$

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