Hockey

Hockey match ended 8:2. How many different matches could be?

Result

n =  45

Solution:

n=C8(10)=(108)=10!8!(10−8)!=10⋅92⋅1=45n = C_{{ 8}}(10) = \dbinom{ 10}{ 8} = \dfrac{ 10! }{ 8!(10-8)!} = \dfrac{ 10 \cdot 9 } { 2 \cdot 1 } = 45

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