Hockey

The hockey match ended 8:2. How many different matches could be?

Correct answer:

n =  45

Step-by-step explanation:

$n=C_8(10)=\left({\displaystyle \genfrac{}{}{0px}{}{10}{8}}\right)={\displaystyle \frac{10!}{8!(10-8)!}}={\displaystyle \frac{10\cdot 9}{2\cdot 1}}=45$

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