# Hockey

Hockey match ended 8:2. How many different matches could be?

Correct result:

n =  45

#### Solution:

$n={C}_{8}\left(10\right)=\left(\genfrac{}{}{0px}{}{10}{8}\right)=\frac{10!}{8!\left(10-8\right)!}=\frac{10\cdot 9}{2\cdot 1}=45$

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