Determine the quotient and the second member of the geometric progression where a3=10, a1+a2=-1,6 a1-a2=2,4.

Correct result:

q =  -5
a2 =  -2


 a3=10 a1+a2=1.6 a1a2=2.4 a1=(1.6+2.4)/2=25=0.4 a2=1.6a1=1.60.4=2 a2=qa1 q=a2/a1=(2)/0.4=5

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