Shopping meeting

Kate left the store with a heavy purchase at a constant speed of 0.5 m/s. Her brother Michael ran to help her at a constant speed of 3.25 m/s. How many meters did Kate have to walk with her shopping before meeting Michael if the store is 300 m from the house?

Final Answer:

k =  40 m

Step-by-step explanation:

$$\begin{gathered} v_1=0.5\text{m/s} \\ {v}_2=3.25\text{m/s} \\ s=300\text{m} \\ v=v_1+v_2=0.5+3.25=\frac{15}{4}=3.75\text{m/s} \\ s=vt \\ t=s/v=300/3.75=80\text{s} \\ k=v_1\cdot t=0.5\cdot 80=40\text{m} \end{gathered}$$

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