Right isosceles triangle

What can be the area of a right isosceles triangle with a side length of 8 cm?

Correct result:

S1 =  32 cm2
S2 =  16 cm2

Solution:

a=8 cm  S1=a⋅ a2=8⋅ 82=32 cm2
c=8 cm  c2=x2+x2  x=c/2=8/2=4 2 cm≐5.6569 cm  S2=x⋅ x2=5.6569⋅ 5.65692=16 cm2

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