Octagonal mat

Octagonal mat formed from a square plate with a side of 40 cm so that every corner cut the isosceles triangle with leg 3.6 cm. What is the content area of one mat?

Correct result:

S =  1574.08 cm2

Solution:

A=3.62/2=16225=6.48 S=4024 A=4024 6.48=3935225=3935225 cm2=1574.08 cm2



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