Quadrilateral-trapezoid 3172

We cut two triangles from the rectangular plate so that the resulting quadrilateral-trapezoid with the same arm lengths has an area of 32 cm2, and one of its bases is twice as long as the other. What is the area of the two triangles that make up the waste?

Correct answer:

S =  10.6667 cm2

Step-by-step explanation:

a=2c 32 = (a+c)h/2 S = a h  32 64 = (a+a/2)h 128= 3ah ah = 128/3 S1=128/3=312842.6667 S = S1  32 S=S132=42.666732=10.6667 cm2

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