Area of iso-trap

Find the area of an isosceles trapezoid if the lengths of its bases are 16 cm and 30 cm, and the diagonals are perpendicular to each other.

Correct result:

A =  529 cm2

Solution:

c=16 cm a=30 cm  a2=x2+x2 x=a/2=30/2=15 2 cm21.2132 cm  c2=y2+y2 y=c/2=16/2=8 2 cm11.3137 cm  d=x+y=21.2132+11.3137=23 2 cm32.5269 cm  h1=x2(a/2)2=21.21322(30/2)2=15 cm h2=y2(c/2)2=11.31372(16/2)2=8 cm  h=h1+h2=15+8=23 cm  A1=a+c2 h=30+162 23=529 cm2  A=d d2=32.5269 32.52692=529 cm2



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