# Exponential equation

Determine the value of having y in the expression (3^y): (4^-1)=36. Unknown y is a natural number greater than zero.

Result

y =  2

#### Solution:

$(3^y): (4^{ -1 })=36 \ \\ 4 \cdot \ 3^y=36 \ \\ 3^y=36/4 \ \\ 3^y=9 \ \\ 3^y=3^2 \ \\ y=2$

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