Circuit voltage

Calculate the closed circuit voltage. Calculate the power on the resistors. R1 = 30 ohms, R2 = 10 ohms. I = 0.1A. U =?. The resistors are connected in series, one after the other.

Correct result:

P₁ =  0.3 W
P₂ =  0.1 W
U =  4 V

Solution:

$$\begin{gathered} R_1=30\mathrm{\Omega } \\ {R}_2=10\mathrm{\Omega } \\ I=0.1\text{ A } \\ {U}_1=I\cdot R_1=0.1\cdot 30=3\text{ V } \\ {P}_1=U_1\cdot I=3\cdot 0.1={\displaystyle \frac{3}{10}}={\displaystyle \frac{3}{10}}\text{ W}=0.3\text{ W} \end{gathered}$$

$$\begin{gathered} U_2=I\cdot R_2=0.1\cdot 10=1\text{ V } \\ {P}_2=U_2\cdot I=1\cdot 0.1={\displaystyle \frac{1}{10}}={\displaystyle \frac{1}{10}}\text{ W}=0.1\text{ W} \end{gathered}$$

$U=U_1+U_2=3+1=4\text{ V}$

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