In an electrical 3

In an electrical circuit, R₁ = 4,000 Ω, R₂ = 8,000 Ω, and R₃ = 6,000 Ω are connected in series. The power supply has a voltage of 100 V. Calculate the voltage across R₁, R₂, and R₃.

Final Answer:

U₁ =  22.22 V
U₂ =  44.44 V
U₃ =  33.33 V

Step-by-step explanation:

$$\begin{gathered} R_1=4000\Omega \\ {R}_2=8000\Omega \\ {R}_3=6000\Omega \\ U=100\text{V} \\ R=R_1+R_2+R_3=4000+8000+6000=18000\Omega \\ I=\frac{U}{R}=\frac{100}{18000}=\frac{1}{180}\doteq 0.0056\text{A} \\ {U}_1=R_1\cdot I=4000\cdot 0.0056=22.22\text{V} \end{gathered}$$

$U_2=R_2\cdot I=8000\cdot 0.0056=44.44\text{V}$

$U_3=R_3\cdot I=6000\cdot 0.0056=33.33\text{V}$

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