Two conductors

Two conductors have resistance Rs=5 ohms when connected in series and Rp=1.2 ohms when connected in parallel. Calculate the value of the resistors.

Correct answer:

R1 =  3 Ω
R2 =  2 Ω

Step-by-step explanation:

S=5 Ω P=1.2 Ω  R1+R2=S 1/R1 + 1/R2=1/P R2 + R1=R1 R2/P  (SR1)+R1=R1 (SR1)/P  (5R1)+R1=R1 (5R1)/1.2 0.83333333333333R24.167R+5=0  a=0.833333;b=4.167;c=5 D=b24ac=4.167240.8333335=0.6944444444 D>0  R1,2=2ab±D=1.6666674.17±0.69 R1,2=2.5±0.5 R1=3=3 Ω R2=2

Our quadratic equation calculator calculates it.

 Verifying Solution:   S2=R1+R2=3+2=5 Ω P2=1/R1+1/R21=1/3+1/21=56=1.2 Ω  R2=2=2 Ω

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