Resistors

Two resistors connected in series give the resulting resistance 65Ω and 10.4Ω in parallel. Determine the resistance of these resistors.

Correct result:

R1 =  52 Ω
R2 =  13 Ω

Solution:

 R1+R2=65 1R1+1R2=110.4 R2=65−R1  1R1+165−R1=110.4  R12−65R1+65⋅10.4=0 R12−65R1+676=0 (R1−52)⋅(R1−13)=0  R1=52Ω R2=13Ω 

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