Two resistors connected in series give the resulting resistance 65Ω and 10.4Ω in parallel. Determine the resistance of these resistors.

Correct result:

R1 =  52 Ω
R2 =  13 Ω


 R1+R2=65 1R1+1R2=110.4 R2=65R1  1R1+165R1=110.4  R1265R1+6510.4=0 R1265R1+676=0 (R152)(R113)=0  R1=52Ω R2=13Ω 

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