Ohms

Two resistors of 6 ohms and 8 ohms are connected in parallel to a flat battery U=4.5 V.

Calculate:
a) the total current,
b) the current in the branches.

Correct answer:

I =  1.3125 A
I1 =  0.75 A
I2 =  0.5625 A

Step-by-step explanation:

R1=6 Ω R2=8 Ω U=4.5 V  I1=U/R1=4.5/6=43=0.75 A I2=U/R2=4.5/8=169=0.5625 A  I=I1+I2=0.75+0.5625=1.3125 A



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