Four families

Four families were on a joint trip. The first family had three siblings: Alice, Betty, and Cyril. In the second family were four siblings: David, Eric, Philip, and Gabby. In the third family, there were two siblings, Hugo and Ivy. Three siblings in the fourth family were John, Charles, and Luke. On the way, children were divided into groups so that in each group, there were all children with the same number of brothers and no one else. How could children be divided? Specify all options.

Write us the number of solutions.

Final Answer:

n =  2

Step-by-step explanation:

P = (1,7) n=2



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