Acceleration 43731

The car starts with constant acceleration, and at a distance of 567 m, it has a speed of 12.6 m/s. How long will it take from the start?

Correct answer:

t =  90 s

Step-by-step explanation:

s=567 m v=12.6 m/s  v = a t s = 21 a t2  s = 21 (v/t) t2 = v t/2  t=2 s/v=2 567/12.6=90=90 s   Verifying Solution:  a=v/t=12.6/90=507=0.14 m/s2  s2=21 a t2=21 507 902=567 m v2=a t=507 90=507 90=50630=563=12.6 m/s

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