# Log

if
${\mathrm{log}}_{4}x+{\mathrm{log}}_{8}x={\mathrm{log}}_{b}x$
, what is b?

Correct result:

b =  2.3

#### Solution:

$b={4}^{\frac{1}{1+\frac{log\left(4\right)}{log\left(8\right)}}}=2.3$

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