# Balance

The rod are 1.9 m long hanging weights 4 kg and 1 kg on ends. Where are centre of rod (distance from weight 4 kg) to be in balance?

Result

x =  0.38 m

#### Solution:

$x= \dfrac{ 1.9\cdot 1}{ 4+1} = 0.38 \ \text{ m }$

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