Irregular hexagon

There is an irregular hexagon whose sides are the same length. The opposite sides are parallel; their distance is 237, 195, and193. What is its area?

Correct answer:

S =  89590.8868

Step-by-step explanation:

a1=a2==a6=a a1a4 a2a5 a3a6  h1=d(a1,a4) h2=d(a2,a5) h3=d(a3,a6)  h1=237 h2=195 h3=193  s=31 (h1+h2+h3)=31 (237+195+193)=3625=20831208.3333 S1=s (sh1) (sh2) (sh3)=208.3333 (208.3333237) (208.3333195) (208.3333193)49150.556 a=3h1 h2 h3=3237 195 193207.3863  S1=a h1=207.3863 23749150.556 S2=a h2=207.3863 19540440.3309  S=S1+S2=49150.556+40440.3309=89590.8868

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Showing 1 comment:
Math student
There is an irregular hexagon whose sides are the same length.
If  a1=a2=a3=a4=a5=a6 it is regular hexagon.
There is an irregular hexagon whose opposite sides are the same length....
Then is a=87,18... b=135,68... c=137,99... d=360,84...
Area of hexagons is:
S=Sd-Sa-Sb-Sc  =36875,1 (Sd; Sa; Sb; Sc is area of  equilateral triangels).

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