Trapezium

The lengths of parallel sides of a trapezium are (2x+3) and (x+8), and the distance between them is (x+4). if the area of the trapezium is 590, find the value of x.

Correct answer:

x =  -23.6667

Step-by-step explanation:

S=590 a=2x+3 c=x+8 h=x+4 S=2a+c h 590=((2x+3)+(x+8))/2(x+4)  590=((2x+3)+(x+8))/2 (x+4) 1.5x211.5x+568=0 1.5x2+11.5x568=0  a=1.5;b=11.5;c=568 D=b24ac=11.5241.5(568)=3540.25 D>0  x1,2=2ab±D=311.5±3540.25 x1,2=3.83333333±19.833333333333 x1=16 x2=23.666666666667   Factored form of the equation:  1.5(x16)(x+23.666666666667)=0 x>0 x=x2=(23.6667)=371=233223.6667 a=2 x+3=2 371+3=3133=443144.3333 c=x+8=371+8=371+38 3=371+324=371+24=347=347=153215.6667 h=x+4=371+4=371+34 3=371+312=371+12=359=359=193219.6667 S2=2a+c h=23133+347 359=2(44.3333)+(15.6667) (19.6667)=590

Our quadratic equation calculator calculates it.




Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?

You need to know the following knowledge to solve this word math problem:

Units of physical quantities:

Grade of the word problem:


 
We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: