Isosceles right triangle

Contents of an isosceles right triangle is 18 dm2. Calculate the length of its base.

Result

c =  8.485 dm

Solution:

S=18 S=ab/2 a=b a=2⋅ S=2⋅ 18=6 b=a=6 c=a2+b2=62+62=6 2≐8.4853=8.485  dm S = 18 \ \\ S = ab/2 \ \\ a = b \ \\ a = \sqrt{ 2 \cdot \ S } = \sqrt{ 2 \cdot \ 18 } = 6 \ \\ b = a = 6 \ \\ c = \sqrt{ a^2+b^2 } = \sqrt{ 6^2+6^2 } = 6 \ \sqrt{ 2 } \doteq 8.4853 = 8.485 \ \text{ dm }

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