Height—the 6183

In the isosceles trapezoid ABCD, the base length is a = 10cm, c = 6cm, and the arm's length is 4cm. Calculate its height—the result round to tenths.

Correct answer:

h =  3.4641 cm

Step-by-step explanation:

$$\begin{gathered} a=10\text{cm} \\ c=6\text{cm} \\ b=4\text{cm} \\ x=(a-c)/2=(10-6)/2=2\text{cm} \\ h=\sqrt{b^2-x^2}=\sqrt{4^2-2^2}=2\sqrt{3}=3.4641\text{cm} \end{gathered}$$

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