Coat of arms

The class created its coat of arms, which had a shape composed of an isosceles trapezoid ABCD (shorter base is a = 4.5 cm long, longer 2a = 9 cm, trapezoid height 6 cm) and a semicircle with center S and diameter AB. Three identical isosceles triangles formed the trapezoid. Pupils painted gray half of the semicircle and the middle field of the trapezoid (central triangle). How many were cm2 areas of the coat of arms gray? Please round the result to one decimal place.

Correct answer:

S =  29.4 cm2

Step-by-step explanation:

a=4.5 cm c=2 a=2 4.5=9 cm v=6 cm  r=a=4.5=29=4.5 cm  S1=2a+c v=24.5+9 6=281=40.5 cm2 S2=π r2/2=3.1416 4.52/231.8086 cm2  S=S1/3+S2/2=40.5/3+31.8086/2=29.4 cm2

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