Arm

Calculate the length of the arm r of isosceles triangle ABC, with base |AB| = 14 cm and a height v=18 cm.

Correct result:

r =  19.31 cm

Solution:

a=14 cm v=18 cm  r2=v2+a22  r=(a/2)2+v2=(14/2)2+182=373=19.31 cm



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