Disc

Circumference of the disk is 78.5 cm. What is the circumference of the circular arc of 32° on the disc?

Correct answer:

o =  24.9873 cm

Step-by-step explanation:

$$\begin{gathered} o_1=78.5\text{ cm } \\ {o}_1=2\pi r \\ r=o_1\mathrm{/}(2\pi )=78.5\mathrm{/}(2\cdot 3.1416)\doteq 12.4937\text{ cm } \\ o=2\cdot r+o\cdot {\displaystyle \frac{32}{360}}=2\cdot 12.4937+24.9873\cdot {\displaystyle \frac{32}{360}}=24.9873\text{ cm} \end{gathered}$$

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