# Disc

Circumference of the disk is 78.5 cm. What is the circumference of the circular arc of 32° on the disc?

Result

o =  24.987 cm

#### Solution:

$o_{ 1 } = 78.5 \ \\ r = o_{ 1 } / (2 \pi) = 78.5 / (2 \cdot \ 3.1416) \doteq 12.4937 \ \\ o = 2 \cdot \ r + o \cdot \ 32/360 = 2 \cdot \ 12.4937 + 24.9873 \cdot \ 32/360 \doteq 24.9873 = 24.987 \ \text{ cm }$

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