Compressive 4914

At what depth does a hydrostatic compressive force of 3.2 MN acting on an area of ​​30 m2 arise in mercury? (mercury density is 13,500 kg/m2)

Correct answer:

h =  0.8054 m

Step-by-step explanation:

F=3.2 106=3200000 S=30 m2 r=13500 kg/m3 p=F/S=3200000/30=3320000106666.6667 Pa g=9.81 m/s2   p = r g h h=p/(r g)=106666.6667/(13500 9.81)=0.8054 m

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