# Hydrostatic force

What hydrostatic force is applied to an area of 30 cm2 in water at a depth of 20 m? (Water density is 1000 kg/m3)

Correct result:

F =  588.6 N

#### Solution:

$S=30 \ cm^2 \rightarrow m^2=30 / 10000 \ m^2=0.003 \ m^2 \ \\ h=20 \ \text{m} \ \\ V=S \cdot \ h=0.003 \cdot \ 20=\dfrac{ 3 }{ 50 }=0.06 \ \text{m}^3 \ \\ ρ=1000 \ \text{kg/m}^3 \ \\ \ \\ m=ρ \cdot \ V=1000 \cdot \ 0.06=60 \ \text{kg} \ \\ g=9.81 \ \text{m/s}^2 \ \\ F=m \cdot \ g=60 \cdot \ 9.81=\dfrac{ 2943 }{ 5 }=588.6 \ \text{N}$

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