Submerged 71144

The cork body floats first in water and then in glycerol. The submerged volume of the cork body in water is 0.0006 m3, and in glycerol, it is 0.0005 m3. The density of water is 1000 kg/m3, and the density of glycerol is 1200 kg/m3. Calculate the buoyant force acting on the same cork body in water and glycerol.

Correct answer:

F1 =  6 N
F2 =  6 N

Step-by-step explanation:

g=10 m/s2 V1=0.0006 m3 V2=0.0005 m3 ρ1=1000 kg/m3 ρ2=1200 kg/m3  F1=V1 ρ1 g=0.0006 1000 10=6 N
F2=V2 ρ2 g=0.0005 1200 10=6=6 N  F1=F2



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