Submerged 71144

The cork body floats first in water and then in glycerol. The submerged volume of the cork body in water is 0.0006 m³, and in glycerol, it is 0.0005 m³. The density of water is 1000 kg/m³, and the density of glycerol is 1200 kg/m³. Calculate the buoyant force acting on the same cork body in water and glycerol.

Correct answer:

F₁ =  6 N
F₂ =  6 N

Step-by-step explanation:

$$\begin{gathered} g=10{\text{m/s}}^2 \\ {V}_1=0.0006{\text{m}}^3 \\ {V}_2=0.0005{\text{m}}^3 \\ {\rho }_1=1000{\text{kg/m}}_3 \\ {\rho }_2=1200{\text{kg/m}}_3 \\ {F}_1=V_1\cdot {\rho }_1\cdot g=0.0006\cdot 1000\cdot 10=6\text{N} \end{gathered}$$

$$\begin{gathered} F_2=V_2\cdot {\rho }_2\cdot g=0.0005\cdot 1200\cdot 10=6=6\text{N} \\ {F}_1=F_2 \end{gathered}$$

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