Body glycerol volume

They will calculate the volume of a body that stretches the force gauge in the air with a force of 80N. After immersion in glycerol with a density of 12 kg. m-3 is a load cell stretched by a force of 30N.

Final Answer:

V =  0.4247 m³

Step-by-step explanation:

$$\begin{gathered} F_1=80\text{N} \\ \rho =12{\text{kg/m}}^3 \\ g=9.81{\text{m/s}}^2 \\ {F}_2=30\text{N} \\ F=F_1-F_2=80-30=50\text{N} \\ F=mg=\rho \cdot V\cdot g \\ V=\frac{F}{\rho \cdot g}=\frac{50}{12\cdot 9.81}=0.4247{\text{m}}^3 \end{gathered}$$

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