Area and perimeter 2

Find the area and the perimeter of a rectangle of length 45 1/2 cm and breadth 16 2/3 cm.

Correct answer:

A =  758.3333 cm²
p =  124.3333 cm

Step-by-step explanation:

$$\begin{gathered} a=45{\displaystyle \frac{1}{2}}=45+{\displaystyle \frac{1}{2}}={\displaystyle \frac{45\cdot 2+1}{2}}={\displaystyle \frac{91}{2}}=45.5\text{ cm } \\ b=16{\displaystyle \frac{2}{3}}=16+{\displaystyle \frac{2}{3}}={\displaystyle \frac{16\cdot 3+2}{3}}={\displaystyle \frac{50}{3}}\doteq 16.6667\text{ cm } \\ A=a\cdot b=45.5\cdot 16.6667={\displaystyle \frac{2275}{3}}{\text{cm}}^2=758\frac{1}{3}{\text{cm}}^2=758.3333{\text{cm}}^2 \end{gathered}$$

$p=2\cdot (a+b)=2\cdot (45.5+16.6667)={\displaystyle \frac{373}{3}}\text{ cm}=124.3333\text{ cm}$

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