Trapezoid - RR

Find the area of the right angled trapezoid ABCD with the right angle at the A vertex;

a = 3 dm b = 5 dm c = 6 dm d = 4 dm

Result

S =  18 dm2

Solution:

a=3 dm b=5 dm c=6 dm d=4 dm S=(a+c)/2⋅ d=(3+6)/2⋅ 4=18=18 dm2a = 3 \ dm \ \\ b = 5 \ dm \ \\ c = 6 \ dm \ \\ d = 4 \ dm \ \\ S = (a+c)/2 \cdot \ d = (3+6)/2 \cdot \ 4 = 18 = 18 \ dm^2

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