Trapezoid - RR

Find the area of the right angled trapezoid ABCD with the right angle at the A vertex;

a = 3 dm b = 5 dm c = 6 dm d = 4 dm

Correct answer:

S =  18 dm²

Step-by-step explanation:

$$\begin{gathered} a=3\text{ dm } \\ b=5\text{ dm } \\ c=6\text{ dm } \\ d=4\text{ dm } \\ S=(a+c)\mathrm{/}2\cdot d=(3+6)\mathrm{/}2\cdot 4=18{\text{dm}}^2 \end{gathered}$$

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