Rhombus MATH

Construct a rhombus M A T H with diagonal MT=4cm, angle MAT=120°

Correct result:

m =  2.309 cm

Solution:

u=4 cm m=u/2/sin60=sinπ/3=2.309 cmu=4 \ \text{cm} \ \\ m=u/2 / \sin 60 ^\circ =\sin π/3=2.309 \ \text{cm}



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Solustion2
Constructions steps:

1. make angle XAY = 120 deg
2. draw its axis p througth point A....
3. draw two paralels lines l1,l2 to axis p at distance 4/2 = 2 cm
4. intersections of legs of angle XAY and l1, l2 is points is points M and T.
5. make point H - use symmetry of point A in mirror of line MTrhombus

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