Rhombus MATH

Construct a rhombus M A T H with diagonal MT=4cm, angle MAT=120°

Result

m =  2.309 cm

Solution:

u=4 cm m=u/2/sin⁡(60∘→ rad)=u/2/sin⁡(60∘⋅ π180 )=4/2/sin⁡(60∘⋅ 3.1415926180 )=2.3094=2.309 cmu=4 \ \text{cm} \ \\ m=u/2 / \sin( 60 ^\circ \rightarrow\ \text{rad})=u/2 / \sin( 60 ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ )=4/2 / \sin( 60 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ )=2.3094=2.309 \ \text{cm}

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Solustion2
Constructions steps:

1. make angle XAY = 120 deg
2. draw its axis p througth point A....
3. draw two paralels lines l1,l2 to axis p at distance 4/2 = 2 cm
4. intersections of legs of angle XAY and l1, l2 is points is points M and T.
5. make point H - use symmetry of point A in mirror of line MTrhombus

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