Cross section

The cross-section ABCD of a swimming pool is a trapezium. Its width AB=14 meters, depth at the shallow end is 1.5 meters, and at the deep end is 8 meters. Find the area of the cross-section.

Result

A =  66.5 m2

Solution:

a=14 m h1=1.5 m h2=8 m h=(h1+h2)/2=(1.5+8)/2=194=4.75 m A=a h=14 4.75=1332=66.5 m2a=14 \ \text{m} \ \\ h_{1}=1.5 \ \text{m} \ \\ h_{2}=8 \ \text{m} \ \\ h=(h_{1}+h_{2})/2=(1.5+8)/2=\dfrac{ 19 }{ 4 }=4.75 \ \text{m} \ \\ A=a \cdot \ h=14 \cdot \ 4.75=\dfrac{ 133 }{ 2 }=66.5 \ \text{m}^2



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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Showing 6 comments:
#
Math student
????that's  correct

#
George
a fiberglass pool that is 12.3 wide and 23.9 long and is 3'9-5'11 deep, would need how many panels?

2 years ago  1 Like
#
Math student
Thank you

#
Math student
Not clear

#
Math student
it is not my problem diagram is right and sum is wrong

#
Math student
Correct. Thank you

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