Swimming pool

A swimming pool 30 meters long is filled with water to a depth of 1 meter at the shallow end and 5 meters at the deep end and abcd the vertical area of the pool has the shape of a trapezium with the area given by S(abcd)= 1/2 (ab + cd) x ad. What is the area of cross-section abcd?

Correct result:

S =  90 m2

Solution:

AD=30 m AB=1 m CD=5 m  S=AB+CD2 AD=1+52 30=90 m2



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Showing 2 comments:
#
Math student
What would be the volume of the pol if it was 20 metres wide

#
Student
(1 + 5)/2 * 20 = 60 m2

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